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A horizontal capillary tube of uniform bore sealed at one end contains dry air trapped by a drop of mercury. The length of the air column is 142mm at `17^0C`.Determine the length of the air column at `25^0C`

Answer Text:
`(V1)/(T1) = (V2)/(T2)`
`142/290 = (V2)/298`
V2 = `(298 times 142)/290`= 145.2mm