Get premium membership and access revision papers with marking schemes, video lessons and live classes.

Processing. Please wait.

Calculate the number of aluminum ions in #250 cm^3# of 0.1 M aluminium sulphate (Avogadro’s Constant = #6.0 times 10^23#)

Answer Text:
Moles #Al_2(SO_4)_3 = 0.1 times 250/1000 = 0.025#
Moles #Al^(3+) = 3 times 0.025 = 0.075#
No. #Al^(3+)# ions =# 0.075 times 6.0 times 1023 = 4.5 times 10^22#