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Form 4 Chemistry Paper 1 Sample Revision Questions With Answers

A $10 cm^3$ volume of concentrated hydrochloric acid of density 1.18 g/ $cm^3$ and purity of 36 percent dissolved in $250 cm^3$ of distilled water. Calculate the morality of the solution. (H = 1, Cl = 35.5)

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Answer Text:
Mass of HCl in $10cm^3$ = $10 times 1.18 times 36/100 = 4.248g$
Moles of HCl in $10cm^3$ = $4.248/36.5 = 0.1164$
Molarity HCl in $250 cm^3$ solution = $0.1164/0.25 = 0.4656 M$