Equations of linear motion
Answer Text: Equations of linear motion:The following equations are applied for uniformly accelerated motion;v = u + ats = ut + ½ #at^2##v^2#= u2 +2asExamples1. A body moving with uniform acceleration of 10 m/#s^2# covers a distance of 320 m. if its initial velocity was 60 m/s. Calculate its finalvelocity.SolutionV2 = u2 +2as= (60) +2×10×320=3600+6400= 10,000Therefore v=# (10,000)^(1/2)#v= 100m/s2. A body whose initial velocity is 30 m/s moves with a constant retardation of 3m/s.Calculate the time taken for the body to come to rest.Solutionv = u + at0= 30-3t30=3tt= 10 seconds.3. A body is uniformly accelerated from rest to a final velocity of 100m/s in 10 seconds.Calculate the distance covered.Solutions=ut + ½ at2=0 × 10 + ½ ×10 × 102= #1000/2#=500m