In the figure below, ABCD is a quadrilateral in whichAB=10cm and angle DAB=angle ABC=#90^0#. P is apoint on AB such that AP=3cm and PB=7cm. ABproduced meets DC produced at Q.Given that APD=#70^0# and BPC = BQC=#30^0#, calculate to one decimal place:(a) The length of AD.(b) The length of BC.(c) The area of quadrilateral ABCD.(d) The length of BQ and hence find the area of triangle ADQ.