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In the figure below, ABCD is a quadrilateral in which
AB=10cm and angle DAB=angle ABC=`90^0`. P is a
point on AB such that AP=3cm and PB=7cm. AB
produced meets DC produced at Q.
Given that APD=`70^0` and BPC = BQC=`30^0`, calculate to one decimal place:

(a) The length of AD.
(b) The length of BC.
(c) The area of quadrilateral ABCD.
(d) The length of BQ and hence find the area of triangle ADQ.