Get premium membership and access revision papers with marking schemes, video lessons and live classes.

Processing. Please wait.

A body mass 0.50kg is attached to the end of a string of length 50cm and whirled in a horizontal circle .If the tension in the string is 81N, determine the velocity of the body. (KCSE 2004 paper 1 question 29).

Answer Text:
Tension ,T = centripetal force = #(m times v times v)/r rightarrow 81 =(0.5 times v times v)/0.5# = 9m/s
V =9m/s.