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The curve of the equation #y=2x + 3x^2#, has #x=-2/3# and x=0 as x-intercepts. The area bounded by the curve, x-axis, #x=-2/3# and x=2 is shown by the sketch below.
Find: (a) #int (2x+3x^2)dx#.
(b) The area bounded by the curve, x-axis, #x=-2/3# and x=2.