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The curve of the equation `y=2x + 3x^2`, has `x=-2/3` and x=0 as x-intercepts. The area bounded by the curve, x-axis, `x=-2/3` and x=2 is shown by the sketch below.

Find: (a) `int (2x+3x^2)dx`.
(b) The area bounded by the curve, x-axis, `x=-2/3` and x=2.