Describe an experiment to find the density of copper turnings using a density bottle and kerosene.
Answer Text: - Measure the mass m_0 of a clean dry empty density bottle. - Fill the bottle partly with copper turnings and measure mass# m_1#.- Fill up the bottle with kerosene up to the neck and measure its mass as # m_2#. - Empty the bottle and rinse it. - Fill it with kerosene and replace it with the stopper, wipe outside dry and measure the mass m_3 of the bottle filled with kerosene.Results Mass of kerosene= #(m_3-m_0) g#Volume of kerosene = #((m_3 -m_0))/0.8 cm^3 #(Since density of kerosene 0.8#gcm^(-3))# Mass of copper turnings =# (m_1-m_0) g #Mass of kerosene present when the bottle is filled with copper turnings and kerosene =# (m_2-m_1)# g Volume of kerosene = #((m_2-m_1))/0.8 cm^3 #Volume of copper turnings = #({(m_3 -m_0) - (m_2-m_1)})/0.8 cm^3 #Therefore density of copper turnings = #(0.8(m_1-m_0) )/({(m_3 - m_0) - (m_2-m_1)})#
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