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Two points A and B have the potential difference v volts. Q coulombs of charge flows between A and B for t seconds. Determine:
i).the electrical energy transformed between the two points in terms of Q.
ii).the power transformed in terms of Q and t.
iii).show that the power transformed is given by P=IV.

Answer Text:
i).E = QV
ii).#P =E/t = (QV)/t#
iii).P =E/t
E = I2Rt
V =IR
R = V/I
#E = (I^2 Vt)/I #
#E = IVt#
#P =E/t =IVt/t = IV#
#P =IV#