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A stick of negligible weight is kept in a horizontal position by the force shown in the diagram below. Calculate the value of y and the magnitude of force Q.

Answer Text:
C.M=A.C.M
3x 0.5 = QxY
1.5 = Q Y…….
Downward forces =
upwards force.
3+Q = 4N ………..
Q = 4-3
= 1N.
= 1.5=1 x Y
1.5 =Y
= Y=1.5M
Q=1N