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On complete combustion of a hydrocarbon gas X, 1.32g of carbon (IV) oxide and 0.54g of water were produced. Calculate the empirical formula of X (C = 12.0, H = 1, O = 16.0)

Answer Text:
1 mole of `CO_2` weighs 44g
44g of `CO_2` contains 12g of c
∴ 1.32 of `CO_2` will contain `12/44 times1.32`
= 0.36g of C
1 mole of `H_2 O` weighs 18g
18g of `H_2O` weigh 2g of H
0.54g of `H_2O` will contain `2 times0.54/18 = 0.06` of H

Element C H
Mass 0.36 0.06
Moles `0.36/12` `0.06/1`

1: 2
Empirical form = `CH_2`