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Using equations, distinguish between the bleaching action of chlorine and Sulphur (IV) oxide.

Answer Text:
Chlorine bleaches by oxidation,
HClO(aq) + dye (colored). -> HCl(aq) + (dye + O) (colorless)
Sulphur (iv) oxide bleaches by reduction
`H_2SO_(3(aq))` +Dye (colored)->`H_2SO_(4(aq))` + (Dye – O)(colorless).